# Mathematics: Post your doubts here!

Discussion in 'International A And AS Level' started by XPFMember, Sep 8, 2011.

1. ### Lee Qian Yi

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Why?

3. ### Thought blocker

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lol... tell me y it wont be like dat? xD
mean temme wat did u do.. like how did u try dis?

4. ### A*****

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Plz anyone helpppp....how will the last 2 parts be solved?

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5. ### Holmes

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Oct/Nov 2007

Help me differentiate plz!

6. ### studyingrobot457

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easy
product rule
this means
-e^(-x)*sin(x)+e^(-x)*cos(x)=0

now solve the equation

7. ### Holmes

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Thanks bro! studyingrobot457
It helped

8. ### NerdyBirdy

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Anyone there to help me I’m kinda stuck in this ques that says
A curve has equation y=2x^2-2x
Find the set of values of x for which y >9
It’s from 9709/12/nov/dec/13

9. ### Thought blocker

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2x^2 - 2x > 9
2x^2 - 2x - 9 > 0
Solve this. And suppose u got solme value a and b where b < a then ur final answer will be x > a and x < b

10. ### Lisa Lunina

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Guys, plz help me on this

11. ### MShaheerUddin

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We have to find integral constant C here

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12. ### Lisa Lunina

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What should i do then? I am really bad when it comes to integral

13. ### MShaheerUddin

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Ive attached the solution see.. If it doesnt help then tell me

14. ### Lisa Lunina

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Ooohh.. I dont see it before haha. Thank you! It helped me a lot

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15. ### Lisa Lunina

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Guys! Plz help me! Im stuck again on integration problem. I cant answer any of the question below.

#### Attached Files:

• ###### Picture2.png
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Last edited: Jan 2, 2018
16. ### Boby Max

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Please help me on functions. I forgotten all the basics.

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17. ### MShaheerUddin

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Here you go lisa ☺️ see attachments

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18. ### Lisa Lunina

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19. ### Hadi Murtaza

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still need help with that ?

20. ### thestudyguy

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9709/12/O/N/17

Each year, the value of a certain rare stamp increases by 5% of its value at the beginning of the year. A collector bought the stamp for \$10 000 at the beginning of 2005. Find its value at the beginning of 2015 correct to the nearest \$100.

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21. ### Hadi Murtaza

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Very similar to compound interest.
F = P(1 + r/100)^n
Where
F = Final amount
P = Initial amount
r = increment
n = number of years

F = 10,000(1 + 5/100)^10
F = 10,000(1.05)^10
F = 10,000(1.6289)
[ F = \$16,289 ≈ \$16,300 ]